Which function has zeros of -8, 1, and 3? A. y = (x − 3)(x + 8)(x − 1) B. y = (x + 1)(x − 8)(x + 3) C. y = x(x + 8)(x − 3) D. y = x(x + 3)(x − 8)

Respuesta :

Answer:

A

Step-by-step explanation:

In each binomial, just flip the sign before the constant, and that number is a zero.

So for example if you have (x+1), a zero would be -1, if you have (x-8), a zero would be 8, etc.

The zeros of a function are the values of x, when the function equals 0.

The function that has zeros of -8, 1 and 3 is: (a) [tex]\mathbf{ y = (x - 3)(x + 8)(x - 1)}[/tex]

The zeros are given as:

[tex]\mathbf{Zeros = -8, 1, 3}[/tex]

Rewrite as:

[tex]\mathbf{x = -8, 1, 3}[/tex]

Equate to 0

[tex]\mathbf{x +8 = 0,\ x - 1 = 0,\ x - 3 = 0}[/tex]

Multiply the equations

[tex]\mathbf{(x +8) \times (x - 1) \times (x - 3) = 0\times 0 \times 0}[/tex]

[tex]\mathbf{(x +8) \times (x - 1) \times (x - 3) = 0}[/tex]

Express as a function

[tex]\mathbf{y = n(x +8) \times (x - 1) \times (x - 3) }[/tex]

Where:

[tex]\mathbf{n \ne 0}[/tex]

The above equation represents functions that have zeros of  -8, 1, and 3

By comparing the options, we have:

[tex]\mathbf{ y = (x - 3)(x + 8)(x - 1)}[/tex] is [tex]\mathbf{y = n(x +8) \times (x - 1) \times (x - 3) }[/tex], where n = 1

Hence, the function that has zeros of -8, 1 and 3 is:

(a) [tex]\mathbf{ y = (x - 3)(x + 8)(x - 1)}[/tex]

Read more about zeros of functions at:

https://brainly.com/question/22101211