contestada

Calcium reacts with water to produce hydrogen and slightly soluble calcium
hydroxide, Ca(OH)2.
Ca(s) + 2 H20(1) --> Ca(OH)2(aq/s) + H2(g).
What will be the volume of hydrogen produced at 27°C and 7.00 x 102 torr when 25
g of calcium and 25 g of water react?

Respuesta :

sebassandin

Answer:

[tex]V=16.65L[/tex]

Explanation:

Hello,

In this case, considering that both 25 g of calcium and water react, the first step is to identify the limiting reactant by considering the yielded moles of hydrogen for the same amount of reactant as follows:

[tex]n_{H_2}^{from\ Ca}=25gCa*\frac{1molCa}{40.1gCa}*\frac{1molH_2}{1molCa} =0.623molH_2\\\\n_{H_2}^{from\ H_2O}=25gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molH_2}{2molH_2O}=0.694molH_2[/tex]

Thus, since calcium yields a smaller amount of hydrogen, it is the limiting reactant so 0.623 moles of hydrogen are yielded. In such a way, by using the ideal gas equation one finds the volume as follows:

[tex]V=\frac{nRT}{P}=\frac{0.623mol*0.082\frac{atm*L}{mol*K}*300K}{700torr*\frac{1atm}{760 torr} } \\ \\V=16.65L[/tex]

Best regards.

Otras preguntas