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Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 6.50 M HCl(aq) are required to react with 8.75 g Zn(s)?

Respuesta :

linahamdan1980

Answer:

41.17

Explanation:

n Zn =  mass / m.wt

      = 8.75 /(65.4) = 0.1338 mole

n HCL = ( from the balanced equation )

     2HCL                  Zn

          2mole   → 1  mole

          x  mole     →             0.1338mole

     n HCL = .268 mole

M= mole/liter

6.50= 0.268/x

so u have0.04117  liter = 41.17 ml

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