Respuesta :

sebassandin

Answer:

[tex]m=4.21g[/tex]

Explanation:

Hello,

In this case, by using the ideal gas equation:

[tex]PV=nRT[/tex]

We can compute the mass of neon gas at the given conditions by firstly computing the moles and also considering the temperature in kelvins (298K):

[tex]n=\frac{PV}{RT}=\frac{1.02atm*5.00L}{0.082\frac{atm*L}{mol*K}*298K}\\ \\n=0.209mol[/tex]

Finally, by using the atomic mass of neon gas (20.18g/mol) we compute the required mass to fill the 5.00-L container:

[tex]m=0.209mol*\frac{20.18g}{1mol}\\ \\m=4.21g[/tex]

Best regards.

Cricetus

The mass of neon gas will be "4.21 g".

Ideal Gas Equation:

Given:

  • Pressure, P = 1.02 atm
  • Volume, V = 5.00 L
  • Temperature, T = 25°C or 298 K

By using Ideal Gas Equation,

⇒ [tex]PV = nRT[/tex]

or,

⇒    [tex]n = \frac{PV}{RT}[/tex]

By substituting the values,

         [tex]= \frac{1.02\times 5.00}{0.082\times 298}[/tex]

         [tex]= 0.209 \ mol[/tex]

hence,

The Mass will be:

= [tex]0.209\times \frac{20.18}{1}[/tex]

= [tex]4.21 \ g[/tex]

Thus the above answer is right.

Find out more information about ideal gas equation here:

https://brainly.com/question/4147359

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