Step-by-step explanation:
Hey there!!
Let's check!
The equation are:
y=x
x - y = 0......(i).
y = x+2
x - y +2 =0......(i).
From equation (i).
[tex]slope(m1) = \frac{ - coeff. \: of \: x}{ coeff. \: of \: y} [/tex]
[tex]m1 = \frac{ - 1}{ - 1} [/tex]
Therefore the slopeof 1st equation is 1.
Now,
From 2nd equation.
[tex]slope(m2) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y} [/tex]
[tex]m2 = \frac{ - 1}{ - 1} [/tex]
Therefore the slope of equation 2 is 1.
As per the condition of parallel lines,
m1= m2
From both equation we got,
m1=m2=1
So, the lines are parallel.
For perpendicular,
m1×m2 = -1
1×1 is not equal to -1.
So, they are not perpendicular.
So, The answer is Option A.
Hope it helps....
