Answer:
c = 0.38 J/(g-°C)
Explanation:
Given that,
Mass of copper, m = 5 g
Initial temperature, [tex]T_i=35^{\circ} C[/tex]
Final temperature, [tex]T_f=22.6^{\circ} C[/tex]
When copper cools, it looses 23.6 J of heat. We need to find the specific heat of copper. The heat lost is given by :
[tex]Q=mc\Delta T[/tex]
c is specific heat
[tex]c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{23.6}{5\times (22.6-35)}\\\\c=0.38\ J/g-^{\circ} C[/tex]
Hence, the correct option is d.
