Answer:
The ball is in the air for approximately 0.45 seconds
Explanation:
We only need to use the information on the height of the table to find the time, since the vertical movement is a movement under the acceleration of gravity, and with no initial velocity in the y-direction (recall that the ball rolls off a 1.0 m high table)
therefore the equation of motion for the vertical component is:
[tex]y_f-y_i=\frac{1}{2}\, g\,t^2[/tex]
which for our information becomes:
[tex]y_f-y_i=\frac{1}{2}\, g\,t^2\\1 = 4.9\,t^2\\t^2=\frac{1}{4.9} \\t=\sqrt{\frac{1}{4.9}} \\t\approx 0.45\,s[/tex]
