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Two children tug on a toy of mass 2.0kg. Costa pulls with a force
of 10.0N[W 30degrees S]. The toy slides with an acceleration of 2.5m/s^2 in the direction of the net force. (North and West are positive)
A) Determine the value of the frictional force acting on the toy.
b)Determine the coeffieicent of friction.

Respuesta :

0259101

Answer:

A) 23 joules

B)8

Explanation: trust me

vi = 18.5 m/s

vf = 46.1 m/s

t = 2.47 s

Find:

d = ??

a = ??

a = (Delta v)/t

a = (46.1 m/s - 18.5 m/s)/(2.47 s)

a = 11.2 m/s2

d = vi*t + 0.5*a*t2

d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s2)*(2.47 s)2

d = 45.7 m + 34.1 m

d = 79.8 m

(Note: the d can also be calculated using the equation vf2 = vi2 + 2*a*d)

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