Respuesta :

kaccm1
3/4*(6x+1)-3*x-(1/4*(2*x-1))=0
X=1
ajeigbeibraheem

3/4 (6x + 1) - 3x = 1/4 (2x - 1) . The purpose of this question is to solve for x.

[tex]\mathbf{x = \dfrac{-4}{13}}[/tex]

Given that:

  • 3/4 (6x + 1) - 3x = 1/4 (2x - 1)

When calculating algebraic expression, we take note of integers in bracket first, then we collect the like terms in order to find the value of x.

[tex]\mathbf{\dfrac{3}{4} (6x + 1) - 3x =\dfrac{1}{4} (2x - 1) }[/tex]

Let's multiply both sides by 4 to eliminate the fraction.

[tex]\mathbf{(\dfrac{3}{4} \times 4) (6x + 1) - 3x =(\dfrac{1}{4} \times 4 ) (2x - 1) }[/tex]

[tex]\mathbf{(3) (6x + 1) - 3x =(1 ) (2x - 1) }[/tex]

  • Open brackets;

18x + 3  - 3x = 2x - 1  

  • By rearrangement;

18x - 3x + 3 = 2x - 1

15x + 3 = 2x - 1

  • Collect like terms

15x - 2x = - 3 - 1

13x = - 4

  • Divide both sides by 13

[tex]\mathbf{\dfrac{13x}{13} = \dfrac{-4}{13}}[/tex]

[tex]\mathbf{x = \dfrac{-4}{13}}[/tex]

Learn more about algebraic expressions here:

https://brainly.com/question/11227332?referrer=searchResults

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