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Calculate the average atomic mass of a
sample of lead that is 24.1% lead-206
(205.974 amu), 22.1% lead-207 (206.976 amu)
and 53.8% lead 208 (207.977 amu).

Respuesta :

theresa88

Answer: 207.217 amu

Work:

203.973 amu *(0.014) = 2.855 amu

205.974 amu *(0.241) = 49.639 amu

206.976 amu *(0.221) = 45.741 amu

207.977 amu *(0.524) = 108.979 amu

2.855 + 49.639 + 45.741 + 108.979 = 207.217amu

Explanation:

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