Suppose that the net external force (push minus friction) exerted on a lawnmower is 51 N. parallel to the ground. The mass of the mower is 24 kg. What is its acceleration?

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Answer:

2.125 m/s^2

Explanation:

Use Newton's second law: Force equals mass times acceleration, F = ma. You know the force (51 N) and you know the mass of the mower (24 kg). Remembering that a Newton is the same as kg-m/s2, solve for acceleration:

F = ma

51 kg-m/s2 = 24 kg * a

2.125 m/s2 =a

If a net external force of 51N is extorted on a 24kg lawnmower parallel to the ground, the acceleration of the mower will be 2.125 m/s².

Given the data in the question;

Net External Force; [tex]F = 51N[/tex]

Mass of the Mower; [tex]m = 24kg[/tex]

Acceleration; [tex]a = ?[/tex]

To determine the acceleration of the mower, we make use of the equation from the Newton's Second Law of Motion:

[tex]F = m\ * \ a[/tex]

Where F is the force exerted, m is the mass and a is the acceleration.

But then, we know that; ( A newton is the same thing as  [tex]1 kg.m/s^2[/tex] )

Hence, Our Net External Force; [tex]F = 51kg.m/s^2[/tex]

We substitute our values into the equation to find acceleration "a"

[tex]51kg.m/s^2 = 24kg\ *\ a\\\\a = \frac{51kg.m/s^2}{24kg} \\\\a = 2.125 m/s^2[/tex]

Therefore, If a net external force of 51N is extorted on a 24kg lawnmower parallel to the ground, the acceleration of the mower will be 2.125 m/s².

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