Answer:
The perimeter of the rhombus is 20 cm
Step-by-step explanation:
Perimeter of a Rhombus
Given the lengths of the two diagonals of a rhombus, let's call them a and b, the perimeter of the rhombus is given by:
[tex]P=2\sqrt{a^2+b^2}[/tex]
The values of the diagonals provided by the question are a=6 cm, b=8 cm, thus the perimeter is:
[tex]P=2\sqrt{6^2+8^2}[/tex]
[tex]P=2\sqrt{36+64}[/tex]
[tex]P=2\sqrt{100}=2*10[/tex]
[tex]P=20\ cm[/tex]
The perimeter of the rhombus is 20 cm
