Respuesta :
Answer:
a
[ FFFF] , [FFFT] , [FFTF] , [FFTT]
[FTFF] , [FTFT] , [FTTF], [FTTT]
[TFFF] , [TFFT] , [TFTF] , [TFTT]
[TTFF] , [TTFT],[TTTF] , [TTTT]
b
[tex]P(A) = \frac{1}{8}[/tex]
c
[tex]P(B) = \frac{1}{4}[/tex]
d
[tex]P(C) = \frac{5}{16}[/tex]
Step-by-step explanation:
From the question we are told that
The number of True - False question is n = 4
The number of answers recorded are k = 4
Generally the outcomes in the sample space are 16 and they are listed below
[ FFFF] , [FFFT] , [FFTF] , [FFTT]
[FTFF] , [FTFT] , [FTTF], [FTTT]
[TFFF] , [TFFT] , [TFTF] , [TFTT]
[TTFF] , [TTFT],[TTTF] , [TTTT]
Generally from the list of the possible outcome we see that the number of outcome where the answers are the same is 2 i.e [TTTT] and [FFFF]
So the probability that all the answers are the same is mathematically represented as
[tex]P(A) = \frac{2}{16}[/tex]
=> [tex]P(A) = \frac{1}{8}[/tex]
Generally from the list of the possible outcome we see that the number of outcome where exactly one answer is true is 4 i.e [FFTF] , [FFFT],[TFFF] , [FTFF]
So the probability that exactly one of the four answers is "True." is mathematically represented as
[tex]P(B) = \frac{4}{16}[/tex]
=> [tex]P(B) = \frac{1}{4}[/tex]
Generally from the list of the possible outcome we see that the number of outcome where at most one of the four answers is true is 5 i.e [FTFF] , [FFFF] , [FFTF] , [FFFT] ,[TFFF]
So the probability that at most one of the four answers is mathematically represented as
[tex]P(C) = \frac{5}{16}[/tex]
The probabilities of all same, exactly one true, and most one of the four are true is 0.125, 0.25, and 0.3125 respectively.
What is probability?
Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.
A section of an exam contains four True-False questions.
A completed exam paper is selected at random, and the four answers are recorded.
Total event = 16
A. The sample space will be shown in the table below.
[tex]\rm Sample \ space = 16 \ \begin{Bmatrix}FFFF & FFFT & FFTF & FFTT \\FTFF & FTFT & FTTF & FTTT \\TFFF & TFFT & TFTF & TFTT \\TTFF & TTFT & TTTF & TTTT\end{Bmatrix}[/tex]
B. The probability that all the answers are the same will be.
Favorable event = 2 ={(TTTT, FFFF}
Then we have the probability,
[tex]\rm P(B) =\dfrac{2}{16} =\dfrac{1}{8} = 0.125[/tex]
C. The probability that exactly one of the four answers is "True".
Favorable event = 4 {(FFFT, FFTF, FTFF, TFFF}
Then we have the probability,
[tex]\rm P(C) =\dfrac{4}{16} =\dfrac{1}{4} = 0.25[/tex]
D. The probability that at most one of the four answers is "True".
Favorable event = 5 {(FFFF, FFFT, FFTF, FTFF, TFFF}
Then we have the probability,
[tex]\rm P(D) =\dfrac{5}{16} =0.3125[/tex]
More about the probability link is given below.
https://brainly.com/question/795909
