// DebugFive1
// Adds your lunch bill
// Burger and hot dog are $2.59
// Grilled cheese and fish are $1.99
// Fries are 89 cents
import java.util.*;
public class DebugFive1
{
public static void main(String args[])
{
Scanner input = new Scanner(System.in);
final double HIGH_PRICE = 2.59;
final double MED_PRICE = 1.99;
final double LOW_PRICE = 0.89;
String usersChoiceString;
int usersChoice;
double bill;
System.out.println("Order please\n1 - Burger\n2 - Hotdog" +
"\n3 - Grilled cheese\n4 - Fish sandwich");
usersChoiceString = input.next();
usersChoice == Integer.parseInt(usersChoiceString);
if(usersChoice == 1 && usersChoice == 2)
bill = bill + HIGH_PRICE;
else
bill = bill + MED_PRICE;
System.out.println("Fries with that?\n1 - Yes\n2 - No";
usersChoiceString = input.next()
usersChoice = Integer.parseInt(usersChoiceString);
if (usersChoice = 1)
bill = bill + LOW_PRICE;
System.out.println("Bill is " + bill);
}
}

Respuesta :

Answer:

See Explanation

Explanation:

The lines with incorrect syntax and corrections are:

1.

Line:

usersChoice == Integer.parseInt(usersChoiceString);

Error

The error is that a relational operator (==) is used instead of an assignment operator (=)

Correction

usersChoice = Integer.parseInt(usersChoiceString);

2.

Line:

System.out.println("Fries with that?\n1 - Yes\n2 - No";

Error:

The line requires a corresponding close bracket

Correction

System.out.println("Fries with that?\n1 - Yes\n2 - No");

3.

Line:

usersChoiceString = input.next()

Error:

The line is not terminated

Correction:

usersChoiceString = input.next() ;

4.

Line

if (usersChoice = 1)

Error

A relational operator is needed

Correction:

if (usersChoice == 1)

Lastly, you need to initialize bill to a value or prompt user for input.

I've added the full source code as an attachment

Ver imagen MrRoyal