Answer:
a) v = 7.28 m/s
b) t = 0.74 s
Explanation:
a) The initial speed of the ball can be calculated using the following equation:
[tex] V_{f}^{2} = V_{0}^{2} - 2gh [/tex]
Where:
[tex]V_{f}[/tex] is the final speed = 0
[tex]V_{0}[/tex] is the initial speed =?
g: is the gravity = 9.81 m/s²
h: is the height = 2.70 m
[tex] V_{0} = \sqrt{2gh} = \sqrt{2*9.81 m/s^{2}*2.70 m} = 7.28 m/s [/tex]
Hence, the initial speed of the ball is 7.28 m/s.
b) To find the time that takes the balls to reach the ceiling we can use the next equation:
[tex] V_{f} = V_{0} - gt [/tex]
[tex] t = \frac{V_{0} - V_{f}}{g} = \frac{7.28 m/s}{9.81 m/s^{2}} = 0.74 s [/tex]
Therefore, the time it takes for the ball to reach the ceiling is 0.74 s.
I hope it helps you!
