Answer:
Step-by-step explanation:
x - the other number (the smaller one)
x+8 - 8 more than the other number (the larger number)
[tex]\dfrac{x+8}x=\dfrac75\\\\(x+8)\cdot5=x\cdot7\\\\5x+40=7x\\^{\quad-40\qquad-40}\\{}\quad5x = 7x-40\\^{\quad-7x\quad-7x}\\-2x=-40\\^{\div(-2)\quad\div(-2)}\\{}\ \ x=20\\\\x+8=28[/tex]