Answer:
The correct answer will be "[tex]9.45\times 10^{-5} \ mol/L[/tex]".
Explanation:
We have:
Moles of solute (Na₂Co₃) = [tex]18.9 \mu \ mol[/tex]
= [tex]18.9\times 10^{-6}[/tex]
[tex]1 \mu \ mol[/tex] = [tex]10^{-6} \ mol[/tex]
Now,
The volume of the solution will be:
⇒ [tex]0.200 \ L[/tex]
∴ [tex]{1 \ mL=0.001 \ L}[/tex]
The formula to find the concentration will be:
⇒ [tex]Concentration = \frac{moles \ of \ solute \ (mol)}{Volume \ of \ solution \ (L)}[/tex]
On substituting the given values, we get
⇒ [tex]=\frac{18.9\times 10^{-6}}{0.200}[/tex]
⇒ [tex]=9.45\times 10^{-5} \ mol/L[/tex]
