The mass of an unidentified rock is 15.5 grams. Students determine the volume of the rock by placing the rock in a cylinder with water. The students calculate the density of the rock. They determine the identity of the rock based on the density ranges in the table.

The students most likely have which type of rock?

Coal
Dolomite
Peridotite
Sandstone

The mass of an unidentified rock is 155 grams Students determine the volume of the rock by placing the rock in a cylinder with water The students calculate the class=

Respuesta :

Answer:

this density is in the range of Peridotite type rocks

Explanation:

In this graduated cylinder exercise we can directly read the volume of the rock

         V = (35 - 30) cm³

          V = 5 cm³

They also indicate the mass of the rock

          m = 15.5 gr.

Density is defined as the ratio of mass to volume

          ρ = 15.5 / 5

          ρ= 3.1  gr /cm³

When checking the attached table this density is in the range of Peridotite type rocks

The type of rock the students mostly like have is Peridotite.

We'll begin by calculating the volume of the rock. This can be obtained as follow:

Volume of water = 30 mL

Volume of water + rock = 35 mL

Volume of rock =?

Volume of rock = (Volume of water + rock) – (Volume of water)

Volume of rock = 35 – 30

Volume of rock = 5 mL

  • Finally, we shall determine the type of rock the students have by calculating the density of the rock. This can be obtained as follow:

Volume of rock = 5 mL = 5 cm³

Mass of rock = 15.5 g

Density of rock =?

Density = mass / volume

Density of rock = 15.5 / 5

Density of rock = 3.1 g/cm³

  • Comparing the density of the rock (i.e 3.1 g/cm³) with those given in table above, we can conclude that the rock is peridotite

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