Billy, a mountain goat, is rock climbing on his favorite slope one sunny spring
morning when a rock comes hurtling toward him from a ledge 40.0 m above.
Billy ducks and avoids injury. a) How fast is the rock traveling when it passes
Billy? b) How does this speed compare to that of a car traveling down the
highway at the speed limit of 25 m/s (equivalent to 55 mi/h)?

Respuesta :

Answer:

There is not enough information to solve how fast the rock was traveling

They are both very fast, as mountain goats are very fast, and if he ducks, he was faster than the rock. The speed compares

Explanation:

I did find this tho.

Ver imagen alexargoonkim

This question can be solved by using the law of conservation of energy.

a) The rock is traveling at "28 m/s" when it passes billy.

b) The speed of the rock is "1.12 times" the speed of the car.

a)

We can find the speed of the rock by using the law of conservation of energy:

Loss of Potential Energy = Gain in Kinetic Energy

[tex]mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\v = \sqrt{2gh} \\\\[/tex]

where,

v = speed of the rock = ?

g = acceleration due to gravity = 9.81 m/s²

h = height = 40 m

Therefore,

[tex]v = \sqrt{2(9.81\ m/s^2)(40\ m)}[/tex]

v = 28 m/s

b)

Now, we find the ratio between the speed of the rock and the speed of the car:

[tex]\frac{speed\ of\ rock}{speed\ of\ car} = \frac{28\ m/s}{25\ m/s}\\\\speed\ of\ rock = (1.12)speed\ of\ car[/tex]

Learn more about the law of conservation of energy here:

https://brainly.com/question/20971995?referrer=searchResults

The attached picture explains the law of conservation of energy.

Ver imagen hamzaahmeds