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Both Andrew and Karleigh recorded the distance they ran in x minutes on treadmills. Andrew A 2-column table with 2 rows. Column 1 is labeled Time in Minutes with entries 18, 24. Column 2 is labeled Distance in miles with entries 1.5, 2. Karleigh A 2-column table with 2 rows. Column 1 is labeled Time in Minutes with entries 30, 40. Column 2 is labeled Distance in miles with entries 3, 4. Andrew and Karleigh each run for 1 hour. Which statement explains who ran a greater distance? Andrew ran a greater distance. The slope of the line described by the data in his table increased at a rate of StartFraction 1 Over 10 EndFraction mile per minute compared to Karleigh’s StartFraction 1 Over 12 EndFraction mile per minute. Karleigh ran a greater distance. The slope of the line described by the data in her table increased at a rate of StartFraction 1 Over 10 EndFraction mile per minute compared to Andrew’s StartFraction 1 Over 12 EndFraction mile per minute. Karleigh ran a greater distance. The slope of the line described by the data in her table increased at a rate of StartFraction 1 Over 12 EndFraction mile per minute compared to Andrew’s StartFraction 1 Over 10 EndFraction mile per minute. Andrew ran a greater distance. The slope of the line described by the data in his table increased at a rate of StartFraction 1 Over 12 EndFraction mile per minute compared to Karleigh’s StartFraction 1 Over 10 EndFraction mile per minute.

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reapersans1888

Answer:

ex:Speed (S) is the ratio of the distance (D) covered to the time (t) taken.

That is, S = D/t

Suppose Andrew ran a distance D1 in 1 hour (3600 seconds) at a Speed, say S1, we have

S1 = D1/t

We can then say he ran a distance

D1 = t × S1

= 3600S1

Similarly, let's say Karleigh ran a distance

D2 = t × S2

= 3600S2

Let us compare these two, you will notice that the bigger number between S1 and S2 is going to determine the bigger number between D1 and D2.

Let's choose random numbers for S1 and S2 for clarity, say S1 = 5, S2 = 10

D1 = 3600 × 5

= 18000

D2 = 3600 × 10

= 36000

This makes D2 bigger than D1. this is an example i found on the internet.

Step-by-

hope this helps, good luck

The ratio of the change in distance to the corresponding change in time

gives the speed of a runner.

  • The statement that explains who ran a greater distance is; Karleigh ran a greater distance. The slope of the line described by the data in her table increased at a rate of [tex]\displaystyle \frac{1}{10}[/tex] mile per minute compared to Andrew's [tex]\displaystyle \frac{1}{12}[/tex] mile per minute.

Reasons:

The tables are;

Andrew

[tex]\begin{tabular}{|cc|c|}Time in Minutes&&Distance in miles\\18&&1.5\\24&&2\end{array}\right][/tex]

Karleigh

[tex]\begin{tabular}{|cc|c|}Time in Minutes&&Distance in miles\\30&&3\\40&&4\end{array}\right][/tex]

The duration each on the treadmills is 1 hour = 60 minutes

[tex]\displaystyle Speed = \mathbf{\frac{Change \ in \ distance}{Change \ in \ time}}[/tex]

Therefore;

[tex]\displaystyle Andrew's \ speed = \frac{2 \, miles - 1.5 \, miles}{24 \, minutes - 18\, minutes} = \mathbf{\frac{1}{12} \ mile/minute}[/tex]

[tex]\displaystyle The \ distance \ Andrew \ ran = \frac{1}{12} \ miles/min \times 60 \ min = \mathbf{5 \ miles}[/tex]

[tex]\displaystyle Karleigh's \ speed = \frac{4 \, miles - 3 \, miles}{40 \, minutes - 30 \, minutes} = \mathbf{\frac{1}{10} \, mile/minute}[/tex]

[tex]\displaystyle The \ distance \ Karleigh \ ran = \frac{1}{10} \, miles/min \times 60 \ min = \mathbf{6 \ miles}[/tex]

Therefore;

  • Karleigh ran a greater distance

  • The correct option is; Karleigh ran a greater distance. The slope of the line in her table increased at a rate of [tex]\displaystyle \frac{1}{10}[/tex] mile per minute compared to Andrew's [tex]\displaystyle \frac{1}{12}[/tex] mile per minute.

Learn more about formula for speed here

https://brainly.com/question/24455685

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