A car traveled 180 miles at a constant rate.
Part 1. Complete the table to show the rate at which the car was traveling if it completed the same
distance in each number of hours.
travel time
(hours)
rate of travel (miles per
hour)
5
4.5
3
2.25
Part 2. In the scenario in question 4 write an equation that would make it easy to find the rate at which the car was traveling in miles per hour r, if they traveled for t hours WILL GIVE 80 POINTS 

A car traveled 180 miles at a constant rate Part 1 Complete the table to show the rate at which the car was traveling if it completed the same distance in each class=

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Answer/Step-by-step explanation:

A. Distance travelled at constant rate = 180 miles

Rate of travel (r) = distance travelled (d) /time (t)

Travel time (hrs) ==> rate of travel (miles/hr)

5 ==> 180/5 = 36

4.5 ==> 180/4.5 = 40

3 ==> 180/3 = 60

2.25 ==> 180/2.25 = 80

B. t = time travelled in hrs,

r = rate (miles/hr)

d = distance travelled = 180

Therefore, rate travelled for t hours would be:

[tex] r = \frac{180}{t} [/tex]

The rate of travel gives the average speed the car will be going if it covers

the 180 miles in different times

Part 1. The table showing the rate at which the car was going is presented as follows;

[tex]\begin{array}{|c|cc|} \underline{\mathbf{Travel \ time, \, t\ (hours)}}&&\underline{\mathbf{Rate \ of \ travel \ (miles \ per \ hour)}}\\&&\\5&&36\\&&\\4.5&&40\\&&\\3&&60\\&&\\2.25&&80\end{array}\right][/tex]

Part 2. To  make it easy to find the rate of travel, the following equation may be uses;

  •  [tex]\underline{The \ rate \ of \ travel= \dfrac{180 \ miles}{t \ hours}}[/tex]

Reasons:

Part 1.

The given distance travelled by the car = 180 miles

[tex]The \ rate \ of \ travel= \dfrac{Distance \ traveled}{Time \ taken}[/tex]

Therefore, we have;

[tex]\begin{array}{|c|c|c|} \underline{\mathbf{Travel \ time, \, t\ (hours)}}&\underline{\mathbf{Rate=\dfrac{180}{t} } }&\underline{\mathbf{Rate \ of \ travel \ (miles \ per \ hour)}}\\&&\\5&\dfrac{180}{5} = 36&36\\&&\\4.5&\dfrac{180}{4.5} = 40&40\\&&\\3&\dfrac{180}{3} = 60&60\\&&\\2.25&\dfrac{180}{2.25} = 80&80\end{array}\right][/tex]

Part 2.

The equation that would simplify the finding of the car's travel rate is given

by the following expression;

[tex]The \ rate \ of \ travel= \dfrac{Distance \ traveled}{Time \ taken}[/tex]

Where:

The constant distance traveled = 180 miles

The time taken = t

The equation that will make finding the rate of travel, easy in therefore;

[tex]\underline{The \ rate \ of \ travel= \dfrac{180 \ miles}{t \ hours}}[/tex]

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