If I have 21,000 mL of gas at a temperature of 870C and a pressure of 101 atm, what will be the pressure of the gas if I raise the temperature to 1040C and decrease the volume to 15 liters?

Question

06-10-2020
Chemistry

contestada

If I have 21,000 mL of gas at a temperature of 870C and a pressure of 101 atm, what will be the pressure of the gas if I raise the temperature to 1040C and decrease the volume to 15 liters?

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08253 08253 · Answer 1 · 2020-10-18T18:46:43+02:00

Answer:

We have,

Initial volume is V

1

Initial temprature is T

1

=75

0

C

Initial pressure is P

1

So, final temprature is T

2

=273+75=348K

V

2

=V

1

−

100

15

V

1

=

100

85V

1

Applying the gas formula,

T

1

P

1

V

1

=

T

2

P

2

V

2

348

P

1

V

1

=

T

2

×100

2P

1

×85V

1

T

2

=

100

2×85×348

T

2

=591.6K