I did this one slot of times but I never get it

Answer:
A: [tex]x^{2} \leq 16[/tex]
A is a solution set of the inequality.
This means:
[tex]x^{2} \leq 4[/tex]
∩ (AND)
[tex]x^{2} \geq -4[/tex]
Which can also be written as:
Interval notation: x ∈ [-4, 4]
Set notation: {x | [tex]-4 \leq x \leq 4[/tex] }