symone222003
contestada

A tennis ball is thrown straight up into the air with an initial velocity of 38 m/s.
a. How long does it take to reach its highest point?
b. How high does the ball travel?

Respuesta :

mata84

Answer:

a) 3.9s

b)74m

Explanation:

a) v=u+at

0=38+(-9.8)t

-38=-9.8t

t=-38/-9.8

t=3.877s

t=3.9s

b) s=ut+1/2at²

s=(38×3.9)+1/2(-9.8×3.9²)

s=148.2 -74.529

s=73.671

s=74m

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