Respuesta :
The statements that are true about the graph of the function are
- The function in vertex form is f(x) = (x - 4)^2 - 11.
- The y-intercept of the function is (0,5).
- The function crosses the x-axis twice
Vertex and intercept of a function
The standard equation of a function in vertex form is expreseed as:
a(x-h)^2 + k
Given the quadaratic function f(x) = x^2 - 8x + 5, the expression in vertex form is given as:
f(x) = (x^2-8x + 4^2) - 16 + 5
f(x) = (x-4)^2 - 16 + 5
f(x) = (x-4)^2 - 11
Find the y-intercept.
This is the point here x = 0
f(0) = 0^2 - 8(0) + 5
f(0) = 5
Hence the y-intercept of the function is at (0, 5)
Since the quadratic function has a leading degree of 2, hence the function crosses the x-axis twice
Learn more on vertex and intercepts here: https://brainly.com/question/12778829