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A 55-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an angle of 40.0o above the horizontal. If the tension in the rope is 125 N, how much work is done on the crate to move it 5.0 m?

Respuesta :

Answer:

478.75 J

Explanation:

W=force* displacement

constant speed= (a=0) net F=0

Horizontal component of tension

Tcosx

125Ncos40= 95.76 N

W= (95.76 N)(5 m)

=478.75 J

onyebuchinnaji

The work done in moving the crate across the given distance is 478.75 J.

The given parameters;

  • Mass of the packing create, m = 55 kg
  • Angle of inclination of the rope, Ф = 40°
  • Tension on the rope, T = 125 N
  • Distance through which the crate is the moved, d = 5 m

The work done in moving the crate is the product of the horizontal component of the tension and the distance through which the crate is moved.

The work-done in moving the crate is calculated as;

W = Tcos(Ф) x d

W = 125cos(40) x 5

W = 478.75 J.

Thus, the work done in moving the crate across the given distance is 478.75 J.

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