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Answer:
33%
Step-by-step explanation:
The probability that a card is a Jack, given that it is a face card, can be expressed as the conditional probability:
P left parenthesis J a c k vertical line F a c e right parenthesis equals fraction numerator P left parenthesis J a c k space a n d space F a c e right parenthesis over denominator P left parenthesis F a c e right parenthesis end fraction
The probability that a card is both a Jack AND a face card is 4 over 52, as there are only 4 cards in a deck that have both qualities.
The probability of a face card is12 over 52 as there are a total of 12 face cards in a deck of cards.
So the probability of a card being a Jack given that it is a face card is:
P left parenthesis J a c k vertical line F a c e right parenthesis equals fraction numerator begin display style bevelled 4 over 52 end style over denominator begin display style bevelled 12 over 52 end style end fraction equals 4 over 12 equals 0.33 equals 33 percent sign.
Given that,
In a well-shuffled, standard 52 card deck,
We have to determine,
What is the probability that a card is a Queen, given that it is a black card?
According to the question,
There are 52 card decks,
Let, the card being a jack is A and the card being a face card is B,
[tex]\rm The \ probability \of \ A\ given\ B \ (Conditional \ probability) = \dfrac{Probability \ of \ A \ and\ B}{Probability \ of\ B}[/tex]
Then,
The probability of the card is a jack and a face card:
[tex]\rm The \ probability \of \ Jack\ given\ face \ card \ (Conditional \ probability) = \dfrac{4}{52}\\\\ The \ probability \ of \ Jack\ given\ face \ card \ (Conditional \ probability) = \dfrac{1}{13}[/tex]
All jacks are face cards.
And the probability of there being a face card is,
[tex]\rm The \ probability \of \ face \ card \ (Conditional \ probability) = \dfrac{12}{52}\\\\ The \ probability \ of \ face \ card \ (Conditional \ probability) = \dfrac{3}{13}[/tex]
There are 12 face cards in a deck.
Therefore,
The probability of a card being a jack given that it is a face card is,
[tex]\rm The \ probability \of \ A\ given\ B \ (Conditional \ probability) = \dfrac{Probability \ of \ A \ and\ B}{Probability \ of\ B}\\\\\rm The \ probability \of \ A\ given\ B \ (Conditional \ probability) = \dfrac{\dfrac{1}{13}}{\dfrac{3}{13}}\\\\The \ probability \of \ A\ given\ B \ (Conditional \ probability) = \dfrac{1}{3}\\[/tex]
Convert the probability of a card being a jack given that it is a face card into a percentage,
[tex]\rm The \ probability \of \ A\ given\ B \ (Conditional \ probability) = \dfrac{1}{3}\\\\ The \ probability \of \ A\ given\ B \ (Conditional \ probability) = \dfrac{1}{3} \times 100\\\\ The \ probability \of \ A\ given\ B \ (Conditional \ probability) = 33 \ percent[/tex]
Hence, The probability of a card being a jack given that it is a face card is, 33%.
For more details refer to the link given below.
https://brainly.com/question/15165308