Answer:
Step-by-step explanation:
Given
- Function h(x) = x^2 + ax + b
- h(1) = 0
- h'(1) = 4
To find
Solution
h(1) = 0 ⇒
- 1^2 + 1*a + b = 0 ⇒
- a + b = -1 ------------------> (1)
h'(1) = 4 ⇒ h(4) = 1 ⇒
- 4^2 + 4*a + b = 1 ⇒
- 4a + b = - 15 ------------------> (2)
Considering the equation (1) in the equation (2)
- 3a - 1 = -15
- 3a = -14
- a = - 14/3
and
- b = -1 - a
- b = -1 + 14/3
- b = 11/3