Answer:
This is a chemistry problem i'm having some issues with. I have a test tomorrow and need all the help I can get.
What I thought to do was first figure out the atoms of 57.0g F, which I got 2x10^24.
Then I tried to convert it into grams Co.
Would I just divide it by 6.022x10^23 and then multiply by the molar mass of Co?
Is the answer 195.7g?
Thanks!
Explanation:
The mass of Cobalt that contains the same number of atoms in 57 g of fluorine is 177 g
We'll begin by calculating the number atoms in 57 g of fluorine. This can be obtained as follow:
From Avogadro's hypothesis,
1 mole of F = 6.02×10²³ atoms
But,
1 mole of F = 19 g
Thus,
19 g of F = 6.02×10²³ atoms
Therefore,
57 g of F = [tex]\frac{57 * 6.02*10^{23} }{19}\\\\[/tex]
57 g of F = 1.806×10²⁴ atoms
Finally, we shall determine the mass of Cobalt that contains 1.806×10²⁴ atoms. This can be obtained:
From Avogadro's hypothesis,
6.02*10²³ atoms = 59 g of Co
Therefore,
1.806×10²⁴ atoms = [tex]\frac{59 * 1.806 *10^{24} }{6.02*10^{23} }\\\\[/tex]
1.806×10²⁴ atoms = 177 g of Co
Thus, we can conclude that 177 g of Cobalt (Co) contains the same number of atoms in 57 g of fluorine
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