pls help with year 8 maths

Answer:
see explanation
Step-by-step explanation:
Given a point (x, y ) then its distance from the origin is
d = [tex]\sqrt{x^2+y^2}[/tex]
(a) (2, 3 ) , then
d = [tex]\sqrt{2^2+3^2}[/tex]
= [tex]\sqrt{4 + 9}[/tex]
= [tex]\sqrt{13}[/tex] ≈ 3.6 units ( to 1 dec. place )
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(b) ( - 5, 7 ) , then
d = [tex]\sqrt{(-5)^2+7^2}[/tex]
= [tex]\sqrt{25+49}[/tex]
= [tex]\sqrt{74}[/tex] ≈ 8.6 units ( to 1 dec. place )
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(c) (- 1, 4 )
d = [tex]\sqrt{(-1)^2+4^2}[/tex]
= [tex]\sqrt{1+16}[/tex]
= [tex]\sqrt{17}[/tex] ≈ 4.1 units ( to 1 dec. place )
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(d) (- 4, - 5 ) , then
d = [tex]\sqrt{(-4)^2+(-5)^2}[/tex]
= [tex]\sqrt{16+25}[/tex]
= [tex]\sqrt{41}[/tex] ≈ 6.4 units ( to 1 dec. place )