Answer:
The answer is below
Step-by-step explanation:
The z score is a score used to determine the number of standard deviations by which the raw score is above or below the mean, it is given by the equation:
[tex]z=\frac{x-\mu}{\sigma} \\\\\mu=mean, \sigma=standard\ deviation,x=raw\ score\\\\for\ a\ sample\ n:\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }[/tex]
Given that μ = 650, σ = 50. To find the probability that 5 students who have a mean of 490, we use:
[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{490-650}{50/\sqrt{5} } =-7.16[/tex]
From the normal distribution table, P(x < 490) = P(Z < -7.16) = 0.0001 = 0.01%
Since only a small percentage of people score about 490, hence the local newspaper editor should write a scathing editorial about favoritism
