Answer:
The appropriate answer will be "8.378 km".
Explanation:
The subsequent trip device runner hits B by repeating the bird. Then the time taken by that of the runner around P to hit B would be:
⇒ [tex]P=\frac{1.2556}{7.3}[/tex]
[tex]=0.172 \ hr[/tex]
Although in this time bird has always been perpetually flying.
Distance covered by bird even before runner approach from P to B will indeed be:
= [tex]29.2\times 0.172[/tex]
= [tex]5.0224[/tex]
Apart from the first encounter, the overall distance traveled by bird would be:
= [tex]5.0224+3.3556[/tex]
= [tex]8.378 \ km[/tex]