I need a photo but ill give you some information this will be with exponents.
Write down the problem. Here it is:
2^2(x+3) + 9 - 5 = 32
Resolve the exponent. Remember the order of operations: PEMDAS, which stands for Parentheses, Exponents, Multiplication/Division, and Addition/Subtraction. You can't resolve the parentheses first because x is in the parentheses, so you should start with the exponent, 2^2.2^2 = 4
4(x+3) + 9 - 5 = 32
Do the multiplication. Just distribute the 4 into (x +3). Here's how:
4x + 12 + 9 - 5 = 32
Do the addition and subtraction. Just add or subtract the remaining numbers. Here's how:
4x+21-5 = 32
4x+16 = 32
4x + 16 - 16 = 32 - 16
4x = 16
Isolate the variable. To do this, just divide both sides of the equation by 4 to find x. 4x/4 = x and 16/4 = 4, so x = 4.
4x/4 = 16/4
x = 4
Check your work. Just plug x = 4 back into the original equation to make sure that it checks out. Here's how:
2^2(x+3)+ 9 - 5 = 32
2^2(4+3)+ 9 - 5 = 32
2^2(7) + 9 - 5 = 32
4(7) + 9 - 5 = 32
28 + 9 - 5 = 32
37 - 5 = 32
32 = 32
Credit to wikiHow.com
