Answer:
[tex]x=\frac{1}{2}[/tex]
[tex]x=-1\frac{2}{3}[/tex]
Step-by-step explanation:
[tex]x=\frac{-b±\sqrt{b^{2} +4ac} }{2a}[/tex]
Ignore the A before the ±, it wouldn't let me type it correctly.
6x² + 7x - 5 = 0
a = 6
b = 7
c = - 7
[tex]x=\frac{-(7)±\sqrt{7^{2} +4((6)(-5))} }{2(6)}[/tex]
[tex]x=\frac{-(7)±\sqrt{49 +4((6)(-5))} }{2(6)}[/tex]
[tex]x=\frac{-(7)±\sqrt{49 +120} }{2(6)}[/tex]
[tex]x=\frac{-7±\sqrt{169} }{12}[/tex]
[tex]x=\frac{-7±13 }{12}[/tex]
Two separate equations
[tex]x=\frac{-7+13 }{12}[/tex]
[tex]x=\frac{-7-13 }{12}[/tex]
________________________
[tex]x=\frac{-7+13 }{12}[/tex]
[tex]x=\frac{6 }{12}[/tex]
[tex]x=\frac{1}{2}[/tex]
[tex]x=\frac{-7-13 }{12}[/tex]
[tex]x=\frac{-20 }{12}[/tex]
[tex]x=-1\frac{2}{3}[/tex]
