Answer:
I) 57.5 m
Il) 50 m/s
Explanation:
Given that a boy stands at a certain distance from a large building and blows a whistle.
After 2.3s he hears the echo of the sound. The speed V of the sound will be:
V = 2X / T
Where X is the distance covered
V = 2X / 2.3
V = 0.87X ...... (1)
He moves 50m towards the building and blows his whistle again; this time the echo reaches him after 2.0s.
V = (2×50) / 2
V = 50 m/s
Substitutes the V into equation 1
50 = 0.87X
X = 50 / 0.87
57.5 m
Therefore, the Boys original distance from the building is 57.5m and the
Speed of sound in air is 50m/s
