Answer:
This question appear incomplete
Explanation:
Th absence of options makes the question seem incomplete. However, the simple method to determine the speed at which the ball was released is
speed = distance or height ÷ time
The unit of the speed will be in meter per second (ms⁻¹)
The distance or height will be the maximum height the ball attained. The unit of the distance will be in meters (m)
The time taken is the time the ball spent in air until it got to it's maximum height. The unit of the time will be in seconds (s).
The equations the student should use to determine the speed at which the ball was released is [tex]v_0 = 2h + \frac{1}{4} gt^2[/tex]
Let the time spent in air by the students = t
Let the height attained by the ball = h
let the initial speed of the ball = [tex]v_0[/tex]
In the absence of air resistance, the time to reach maximum height = time to return to the return.
[tex]time \ to \ reach \ maximum\ height = \frac{time \ of \ flight}{2} = \frac{t}{2}[/tex]
The equation for the maximum height reached;
[tex]h = v_0 (\frac{t}{2} ) - \frac{1}{2} g(\frac{t}{2})^2\\\\h = \frac{1}{2} v_0 - \frac{1}{8} gt^2\\\\\frac{1}{2} v_0 = h + \frac{1}{8} gt^2\\\\v_0 = 2h + \frac{1}{4} gt^2[/tex]
Thus, the equations the student should use to determine the speed at which the ball was released is [tex]v_0 = 2h + \frac{1}{4} gt^2[/tex]
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