Respuesta :
Answer:
The distance ran by the runner in the 2 seconds is 2·A
The speed of the runner at the end of the 2 seconds is 2·A
Explanation:
The given information are;
The distance the sprinter is running = 100 m
The initial constant acceleration of the sprinter, a = A
The duration of the initial acceleration, t = 2 s
The initial speed of the printer, u = 0 (The sprinter starts from rest)
The rate with which the sprinter then runs with to the end = Constant speed
Therefor, we have, from the equation of motion;
s = u × t + 1/2 × a × t²
Where;
s = The distance ran by the sprinter
∴ at t = 2 seconds, we have;
s = 0 × 2 + 1/2 × A × 2² = 1/2 × A × 4 = 2·A
The distance ran by the runner in the 2 seconds = 2·A
The speed, v, of the runner at the end of the 2 seconds is given as follows;
v = u + a × t
When t = 2 seconds, we have;
v = 0 + A × 2 = 2·A
The speed of the runner at the end of the 2 seconds = 2·A.
