Answer:
(a) 10 quantities of protein
(b) 2 quantities of protein
Explanation:
Given
[tex]A = 0.0182 x +0.007[/tex]
Solving (a):
Solve for x when A = 0.207
Substitute 0.207 for A
[tex]A = 0.0182 x +0.007[/tex]
[tex]0.207 = 0.0182x + 0.007[/tex]
Solve for 0.0182x
[tex]0.0182x = 0.207 - 0.007[/tex]
[tex]0.0182x = 0.200[/tex]
Solve for x
[tex]x = 0.200/0.0182[/tex]
[tex]x = 10.989010989[/tex]
[tex]x = 11[/tex] (Approximated)
Solving (b):
Solve for x when A = 0.050
Substitute 0.050 for A
[tex]A = 0.0182 x +0.007[/tex]
[tex]0.050 = 0.0182x + 0.007[/tex]
Solve for 0.0182x
[tex]0.0182x = 0.050 - 0.007[/tex]
[tex]0.0182x = 0.043[/tex]
Solve for x
[tex]x = 0.043/0.0182[/tex]
[tex]x = 2.36263736264[/tex]
[tex]x = 2[/tex] (Approximated)