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Given:
Lilly starts hiking along a trail at 3 miles per hour.
Dave starts hiking the same trail from the same starting point at 3.5 miles per hour.
lilly walked 2 miles before Dave started hiking.
To find:
Whether he will catch up to her and write an equation.
Step-by-step explanation:
Let the number of hours when both are hiking be h.
lilly walked 2 miles before Dave started hiking at 3 miles per hour.
Lilly hiking = 2+3h
Dave starts hiking the same trail from the same starting point at 3.5 miles per hour.
Dave hiking = 3.5 h
He will catch her if hiking distance of both are equal.
[tex]2+3h=3.5h[/tex]
Subtract 3h from both sides.
[tex]2=3.5h-3h[/tex]
[tex]2=0.5h[/tex]
Divide both sides by 0.5.
[tex]\dfrac{2}{0.5}=h[/tex]
[tex]4=h[/tex]
Therefore, Dave will catch her after 4 hours.
Dave will catch up Lilly after 4 hours.
Since Lilly starts hiking along a trail at 3 miles per hour, and Dave starts hiking the same trail from the same starting point at 3.5 miles per hour, if Lilly walked 2 miles before Dave started hiking, to determine when he will have catch up to her the following calculation must be performed:
- The initial distance between the two must be divided by the difference between their speeds.
- 2 / (3.5 - 3) = X
- 2 / 0.5 = X
- 4 = X
Therefore, Dave will catch up Lilly after 4 hours.
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