Lilly starts hiking along a trail at 3 miles per hour. Dave starts hiking the same trail from the same starting point at 3.5 miles per hour. If lilly walked 2 miles before Dave started hiking , will he catch up to her ? write a equation ​

Respuesta :

Given:

Lilly starts hiking along a trail at 3 miles per hour.

Dave starts hiking the same trail from the same starting point at 3.5 miles per hour.

lilly walked 2 miles before Dave started hiking.

To find:

Whether he will catch up to her and write an equation.

Step-by-step explanation:

Let the number of hours when both are hiking be h.

lilly walked 2 miles before Dave started hiking at 3 miles per hour.

Lilly hiking = 2+3h

Dave starts hiking the same trail from the same starting point at 3.5 miles per hour.

Dave hiking = 3.5 h

He will catch her if hiking distance of both are equal.

[tex]2+3h=3.5h[/tex]

Subtract 3h from both sides.

[tex]2=3.5h-3h[/tex]

[tex]2=0.5h[/tex]

Divide both sides by 0.5.

[tex]\dfrac{2}{0.5}=h[/tex]

[tex]4=h[/tex]

Therefore, Dave will catch her after 4 hours.

Dave will catch up Lilly after 4 hours.

Since Lilly starts hiking along a trail at 3 miles per hour, and Dave starts hiking the same trail from the same starting point at 3.5 miles per hour, if Lilly walked 2 miles before Dave started hiking, to determine when he will have catch up to her the following calculation must be performed:

  • The initial distance between the two must be divided by the difference between their speeds.
  • 2 / (3.5 - 3) = X
  • 2 / 0.5 = X
  • 4 = X

Therefore, Dave will catch up Lilly after 4 hours.

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