(a) The formula for area of a triangle is expressed in terms of h as [tex]h = \frac{2A}{b}[/tex]
(b) The height, h of the triangle is calculated as 4 in
Given:
area of a triangle, [tex]A= \frac{1}{2} bh[/tex]
To find:
- the area in terms of h
- the height, h, of the triangle when the Area, A = 18 in² and base, b = 9 in
(a) The formula, (area of a triangle) is expressed in terms of h as;
[tex]A = \frac{1}{2} bh\\\\multiply \ both \ sides \ of \ the \ equation \ by\ 2\\\\bh = 2A\\\\divide \ through \ by \ b\\\\\frac{bh}{b} = \frac{2A}{b} \\\\h = \frac{2A}{b}[/tex]
(b) The height, h of the triangle is calculated as
[tex]h = \frac{2A}{b}\\\\Recall , A = 18 \ in^2 , \ b = 9\ in\\\\h = \frac{2\times 18}{9}\\\\h = 4 \ in[/tex]
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