contestada

ASAP MULTIPLE CHOICE WILL MARK BRAINLIEST
An atom of rubidium has 37 protons and 48 neutrons. The atom loses one electron.
What will be the charge on the ion that forms?

36
+1
−36
−1

Respuesta :

Answer:

+1

Explanation:

capsasha2

Answer:

  1. -1
  2. 36

Step-by-step explanation:

  1. "Loses" means subtraction, decrease, or negative. So, a loss of 1, can also be represented by -1.
  2. If protons and electrons can be represented by the same number (37), then a loss of 1 is just, 37 - 1. 37 - 1 = 36.

I hope this helps!

Otras preguntas