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Caleb’s school is five blocks due north of his home, and the library is two blocks due west of his home. If each city block is a square with sides measuring 275 feet, which of the following is the closest to the straight-line distance from Caleb’s school to the library?

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Answer:

The closest straight-line distance from Caleb's school to the library is:

  • 1480.92 feet

Step-by-step explanation:

Imagine a triangle, where five blocks are a side and two blocks another side, to obtain the closest straight-line distance from Caleb's school to the library you can use the Pythagoras theorem, where the hypotenuse is the closest straight-line:

  • [tex]perpendicular^{2} +base^{2} =hypotenuse^{2}[/tex]

Clearing the hypotenuse is:

  • [tex]\sqrt{perpendicular^{2}+base^{2}}= hypotenuse[/tex]

Now, you only need to identify the distance in each case:

Five blocks = 275 feet * 5 = 1375 feet.

Two blocks = 275 feet * 2 = 550 feet.

At last, you must replace the distances found in the equation cleared:

  • [tex]\sqrt{1375 feet^{2}+550 feet^{2}}= hypotenuse[/tex]
  • Hypotenuse or closest straight-line = 1480.92 feet.

Identifying this, the closest straight-line distance from Caleb's school to the library is 1480.92 feet.

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