Mr. Ratchett, an elderly American, was found murdered in his train compartment on the Orient Express at 7 AM. When his body was discovered, the famous detective Hercule Poirot noted that Ratchett had a body temperature of 28 degrees. The body had cooled to a temperature of 27 degrees one hour later. If the normal temperature of a human being is 37 degrees and the air temperature in the train is 22 degrees.

Required:
Estimate the time of Ratchett's death using Newton's Law of Cooling.

Respuesta :

Answer: Mr. Ratchett died approximately at 2AM.

Step-by-step explanation: Newton's Law of Cooling shows the cooling rate between a body and the environment, by stating that the rate is proportional to the difference in temperatures between them.

Mathematically, it is represented as:

[tex]\frac{dQ}{dt}=\alpha.A.(T_{s}-T)[/tex]

This differential equation solved, gives the solution:

[tex]T(t)=T_{s}+(T_{0}-T_{s})e^{-kt}[/tex]

where

[tex]T_{s}[/tex] is temperature of the environment

[tex]T_{0}[/tex] is the initial temperature of the body

k is a parameter dependent of heat transfer coefficient, heat capacity and area of the body

t is time required to change the temperature

For the murder on the Orient Express, first determine parameter k.

In 1 hour, Mr. Ratchett's body decrease 1°:

[tex]27=22+(28-22)e^{-1k}[/tex]

[tex]5=6e^{-k}[/tex]

[tex]e^{-k}=\frac{5}{6}[/tex]

[tex]ln(e^{-k})=ln(0.834)[/tex]

k = 0.1823

Using the parameter, find estimate time:

[tex]28=22+(37-22)e^{-0.1823t}[/tex]

[tex]6=15e^{-0.1823t}[/tex]

[tex]ln(e^{-0.1823t})=ln(0.4)[/tex]

0.1823t = 0.9163

[tex]t=\frac{0.9163}{0.1823}[/tex]

t ≈ 5 hours

The body was found at 7AM. So, it took approximately 5 hours to cool down to 28° at that time. Therefore, Mr. Ratchett died at 2AM.