The distance traveled by the apply after being released is 127.45 m.
The given parameters;
time of motion of the apple, t = 5.1 s
initial velocity of the apple, u = 0
The distance traveled by the apply is calculated by applying second kinematic equation as shown below.
Assuming downward motion to be positive.
[tex]s = ut + \frac{1}{2} gt^2\\\\s = 0 + 0.5\times 9.8 \times 5.1^2\\\\s = 127.45 \ m[/tex]
Thus, the distance traveled by the apply after being released is 127.45 m.
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