Answer:
3750 m
Step-by-step explanation:
This question can be solved using law of equation of motion
[tex]v^2 = u^2 + 2as[/tex]
where v is the final velocity
u is the initial velocity
a is the acceleration
and
s is the distance travelled
________________________________
given
final velocity = v = 0 since it is given that plane stops
u = 150 m/s
a = -3m/s2
using the above values in the given equation
[tex]v^2 = u^2 + 2as\\0 = 150*2 + 2*-3s\\0 = 22500 - 6s\\=> 6s = 22500\\=> s = 22500/6 = 3750[/tex]
Thus, plane will travel 3750 m before it stops.
