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3. A student takes an object with an accepted mass of 200.00 grams and masses it on his own balance. He
records the mass of the object as 196.5 g. What is his percent error?
I

Respuesta :

Stephen46

Answer:

The answer is 1.75 %

Explanation:

The percentage error of a certain measurement can be found by using the formula

[tex]P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ [/tex]

From the question

actual number = 200 g

error = 200 - 196.5 = 3.5

We have

[tex]p(\%) = \frac{3.5}{200} \times 100 \\ [/tex]

We have the final answer as

1.75 %

Hope this helps you