Answer:
[tex]m_{Pb(SO_4)_2}=1.996 g[/tex]
Explanation:
Hello.
In this case, given the formula of the lead (IV) sulfate, we can compute its molar mass as shown below:
[tex]M_{Pb(SO_4)_2}=m_{Pb}+2*m_S+2*4*m_O\\\\M_{Pb(SO_4)_2}=207.2+2*32+2*4*16\\\\M_{Pb(SO_4)_2}=399.2g/mol[/tex]
Thus, by applying the following mole-mass relationship, we obtain the mass of 0.005 moles of lead (IV) sulfate:
[tex]m_{Pb(SO_4)_2}=0.005mol*\frac{399.2g}{1mol} \\\\m_{Pb(SO_4)_2}=1.996 g[/tex]
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