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Simon has a quarter, dime, nickel, and penny in his pocket. He wants to buy a snack at the canteen that costs 40¢. If he pulls out one coin at a time, what is the probability that the first 3 coins that are equal to $0.40?
The completed formula is ___c____3=____
There are___items. He will choose____

Respuesta :

mayamc32

Answer:

It would be a 3/4 chance that he will pull the right 4 coins.

Step-by-step explanation:

The probability that the first 3 coins are equal to $0.40 will be 1/4

How to explain the probabaility?

  • Q=event of pulling a quarter (25 cents)
  • D=event of pulling a dime (10 cents)
  • N=event of pulling a nickel (5 cents)
  • P=event of pulling a penny (1 cent)

Simon needs to pull out the penny last so that the first three coins add up to $0.40. We assume the coins are wrapped so it is a random choice.

For the first coin, the probability of not pulling a penny is 3/4, similarly, for the second coin, the probability of not pulling a penny is 2/3,

For the third coin, the probability of not pulling a penny is 1/2,

P(3 coins but no penny) = (3/4*2/3*1/2) = 1/4

Learn more about probability on:

https://brainly.com/question/24756209

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