Respuesta :
The force between two touching grapefruits each with a radius of 0.08 meters and a mass of 0.45 kg is 5.27 * 10⁻¹⁰ N
Newton's law of gravitation is given by:
F = Gm₁m₂/r²
Where F is the force, m₁, m₂ are masses, r is the distance between the two masses and G is the gravitational constant = 6.67 * 10⁻¹¹ Nm²/kg²
Given that m₁ = m₂ = 0.45 kg, r = 0.08 + 0.08 = 0.16 m, hence:
F = 6.67 * 10⁻¹¹ Nm²/kg² * 0.45 kg * 0.45 kg / 0.16²
F = 5.27 * 10⁻¹⁰ N
The force between two touching grapefruits each with a radius of 0.08 meters and a mass of 0.45 kg is 5.27 * 10⁻¹⁰ N
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