Answer:
A
Explanation:
Considering question A
Mass of original sample is [tex]m_o = 0.945 \ g [/tex]
Mass of NH4Cl is [tex]m_n = 0.116 \ g [/tex]
Percent of NH4Cl is [tex]k = 12.275 \% [/tex]
B
Mass of NaCl [tex]m_k = 0.359 \ g [/tex]
C
Mass of SiO2 [tex]m_e = 0.46[/tex]
D
Mass of original sample [tex]m_o = 0.945 \ g [/tex]
Differences in these weights (g) (use the absolute value of the difference)
recovery of matter [tex]G = 0.01 \ g [/tex]
The correct option is C
From the question we are told that
The mass of evaporating dish on #1 is [tex]m_1 = 38.646 \ g[/tex]
The mass of evaporating dish and original sample [tex]m_2 = 39 591 \ g[/tex]
The mass of evaporating dish after subliming [tex]NH_4Cl [/tex] is [tex]m_3 = 39.4750 \ g[/tex]
Generally the mass of the original sample is mathematically represented as
[tex]m_o = m_2 - m_1[/tex]
=> [tex]m_o = 39 591 - 38.646 [/tex]
=> [tex]m_o = 0.945 \ g [/tex]
Generally the mass of [tex]NH_4Cl[/tex] is mathematically represented as
[tex]m_n = m_2 - m_3[/tex]
=> [tex]m_n = 39 591 - 39.4750[/tex]
=> [tex]m_n = 0.116 \ g [/tex]
The Percent [tex]NaH_4 Cl (g)[/tex]
[tex]k = \frac{ m_n}{m_o} *100[/tex]
=> [tex]k = \frac{0.116 }{0.945} *100[/tex]
=> [tex]k = 12.275 \% [/tex]
Considering question B
The mass of evaporating dish #2 is [tex]m_g = 38700\ g[/tex]
The mass of watch glass is [tex]m_a = 28 299 \ g[/tex]
The mass of evaporating dish #2, watch glass and NaCl [tex]m_b = 67,355 \ g[/tex]
Generally the mass of NaCl is
[tex]m_k = m_b -[m_g + m_a][/tex]
=> [tex]m_k = 67,355 -[38700 + 28 299][/tex]
=> [tex]m_k = 0.359 \ g [/tex]
Considering question C
The mass of evaporating dish is [tex] m_p= 38.645[/tex]
The mass of evaporating dish and SiO2 [tex]m_s = 39.105 \ g[/tex]
Generally the mass of SiO2 is mathematically represented as
[tex]m_e = 39.105 - 38.645[/tex]
=> [tex]m_e = 0.46[/tex]
Considering D
The mass of the original sample is [tex]m_o = 0.945 \ g[/tex]
Generally the experimental mass recovered (NH_4Cl,NaCl, SiO2 ) is mathematically evaluated as
[tex]M =0.116 + 0.46 + 0.359[/tex]
[tex]M = 0.935 \ g [/tex]
Generally the differences in these weights (g) of recovery of matter is mathematically represented as.
[tex]G =0.945- 0.935 [/tex]
=> [tex]G = 0.01 \ g [/tex]
While drying the NaCl, the liquid boiled and some splattered out of the evaporating dish, causing the recovered mass to be lower.
